the radii of the end of a bucket 16 cm high are 20 cm and 8 cm . find the curve surface area of the bucket
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hey mate
if we unfold the cylindrical curved shape of a bucket we get a trapezium
Where the parallel sides are
2πr=2*22/7*20=125.71cm(from top)
2πr=2*22/7*8=50.28cm
height =16cm
CSA Of bucket =area of trapezium =1/2*h*sum of parallel sides =1/2*16*(125.71+50.28)=1407.92cm²
u can also do it by taking the frustum
hope it helps you
if we unfold the cylindrical curved shape of a bucket we get a trapezium
Where the parallel sides are
2πr=2*22/7*20=125.71cm(from top)
2πr=2*22/7*8=50.28cm
height =16cm
CSA Of bucket =area of trapezium =1/2*h*sum of parallel sides =1/2*16*(125.71+50.28)=1407.92cm²
u can also do it by taking the frustum
hope it helps you
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