Question

The radii of the ends of a bucket 12 cm high are 15 cm and 10 cm. The curved surface area of the bucket is ​

Answer 1

Answer:

1021.42cm²

Step-by-step explanation:

Here,

Height, h = 12 cm

R = 15cm

r = 10cm

Now,

we need slant height.

.'. Slant height (l) = whole root over h²+(R-r)²

= whole root over 12²+(15-10)²

= whole root over 144+25

= whole root over 169

= 13

.'. CSA of the bucket = pie x l (R+r)

= 22/7 x 13(15+10)

= 22/7 x 13 x 25

= 7150/7

= 1021.42 cm²

Answer 2

Answer:

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Step-by-step explanation:

Radius of top the bucket (R) = 12cm

Radius of bottom of the bucket (r) = 10cm

And

Height of the bucket (H) = 15 cm

Therefore,

Slant height (L) = (√H)2 + (R-r) 2

= (√15)2 + (10-12)2

=√225+(2)2

=√225+4

=√229

Curved surface area of bucket =π L +(R+r) cm2

=22/7×26(10+12)cm2

=(22×26)×22/7cm2

=(22×26×22)/7cm2

12672cm2