Question

The radii of the ends of a frustum of a cone 45 CM by 28 cm and 7 cm find its volume the curved surface area and the total surface area

Answer 1

Answer:

Given,  

R = 28 cm

r= 7cm

H= 45cm

volume of frustum = $\pi$ /3H (R^2 + r^2 + R×r)

=>  $\pi$ /3×45 ( 28$^{2}$ +7$^{2}$ +28 ×7)

=> $\pi$/ 3×45( 784+49+196)

=> 22×15/7(784+49+196)

=> 22×15

330/7 (1029)

1029/7=147

330×147=48510$cm^{3}$

Total surface area = 48510$cm^{3}$

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@GauravSaxena01