the radii of the inner and external surface of hollow spherical shell are 3 cm and 5 cm respectively. if it is melted and casted into a solid cylinder of diameter 14 cm,fi d the height of the cylinder?
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let the inner radius be r and external radius be R .
we have ,inner radius=r =3cm
external radius=R=5cm
radius of cylinder=d/2=r1=14cm/2=7
volume of shell=volume of cylinder
4/3×22/7×R^3-(4/3×22/7×r^3)=22/7r1^2×h
4/3(R^3-r^3)=7^2×h
4/3(5^3-3^3)=49h
4/3(125-27)=49h
4/3×98=49h
4/3×98/49=h
8/3=h
h=8/3cm
Hence height of cylinder=8/3cm
we have ,inner radius=r =3cm
external radius=R=5cm
radius of cylinder=d/2=r1=14cm/2=7
volume of shell=volume of cylinder
4/3×22/7×R^3-(4/3×22/7×r^3)=22/7r1^2×h
4/3(R^3-r^3)=7^2×h
4/3(5^3-3^3)=49h
4/3(125-27)=49h
4/3×98=49h
4/3×98/49=h
8/3=h
h=8/3cm
Hence height of cylinder=8/3cm
How 2 will come ?
U see there is a diameter not radius
r = 2/d
thanku for reminding me
You're welcome but m also workout
now is it correct
How u cancel 4/3×98/49=h
Yes m do it
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