The radii of the internal and external surface of a hollow spherical shell are 3 cm and 5 cm respectively. If it is melted and casted into a solid cylinder of diameter 14 cm, find the height of the cylinder.
Answers
Answered by
11
Answer:
2.68 cm
Step-by-step explanation:
Given:
Internal radii of the sphere = r₁ = 3 cm.
External radii of the sphere = r₂ = 5 cm.
Volume of the sphere = (4/3)π(r₂³ - r₁³)
= (4/3)π(5³ - 3³)
= (4/3)π(125 - 27)
= 410.67 cm³
∴ Volume of cylinder = πr²h
⇒ 410.67 = (22/7) * (7)² * h
⇒ 410.67 = 22 * 7 * h
⇒ h = 2.68 cm.
Hope it helps!
Answered by
3
Internal radius = 3cm, External radius = 5cm.
Volume of sphere = 4/3 × pie (5 cube - 3 cube).
= 4/3 × 22/7 × (125 - 27).
= 4/3 × 22/7 × (98).
= 410.67 cm cube.
Volume of cylinder = pie × r square × h.
410.67 = 22/7 × 7 × 7 × h.
410.67 = 154 × h.
h = 2.68 cm.
Hope it helps you.
Mark me as the brainliest please.
Volume of sphere = 4/3 × pie (5 cube - 3 cube).
= 4/3 × 22/7 × (125 - 27).
= 4/3 × 22/7 × (98).
= 410.67 cm cube.
Volume of cylinder = pie × r square × h.
410.67 = 22/7 × 7 × 7 × h.
410.67 = 154 × h.
h = 2.68 cm.
Hope it helps you.
Mark me as the brainliest please.
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