The radii of the internal and external surfaces of a hollow spherical shell are 3 cm and 5 cm respectively. If it is melted and recast into a solid cylinder of height 22/3 cm, find the diameter of the cylinder.
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Answer:
The total surface area of a cylinder is equal to the sum of areas of all its faces. The total surface area with radius 'r', and height 'h' is equal to the sum of the curved area and circular areas of the cylinder. TSA = 2π × r × h + 2πr2= 2πr (h + r) Square units.
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14cm
Step-by-step explanation:
Given that, Internal radius of the sphere = 3 cm = r1 External radius of the sphere = 5 cm = r2 Height of cylinder = 2 2/3 cm = 8/3 cm = h Volume of spherical shell = Volume of the cylinder Diameter of the cylinder = 2 (radius) = 14 cm
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