Question

the radii of the internal external of metallic spherical shell are 3 cm and 5 cm respectively it is melted and recast into a solid right circular cylinder of the height 10 2/3 find the diameter of the base of the cylinder​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

$\frac{4}{3} \times \pi(5) ^{3} - \frac{4}{3 } \times ( {3})^{3} \\ \frac{4}{3} \times \pi \times (125 - 27) \\ \frac{392\pi}{3 } \\ let \: the \: diameter \: of \: the \: base \: of \: the \: cylinder \: be \: r \: cm \\ \frac{392}{3} \times \pi = \pi (\frac{r}{2})^{2} \times ( \frac{32}{3} ) \\ (\frac{r}{2})^{2} = \frac{392}{32} \\ ( \frac{r}{2})^{2} = \frac{49}{4} \\ \frac{r}{2} = \frac{7}{2} \\ r = 7 \\ answer \: is \: 7 \: cm$

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