Question

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and
7 cm, respectively. The curved surface area of the bucket is

Answer 1

Solution :

Given:

• The radius of top of bucket, r₂ = 28cm.
• The radius of bottom of bucket, r₁ = 7cm.
• Slant height of bucket, l = 45cm.

Need to find:

• The (CSA) curved surface area of the bucket.

Explanation:

We know that, bucket is always is in the form of frustum cone. So, we will apply CSA of frustum formula to find the curved surface area of the bucket

We know that, if we are given with slant height of bucket, radii of the top and bottom of a bucket, then we have the required formula, that is,

• CSA of frustum = πl(r₁ + r₂).

By using the required formula and plugging all the given values in the formula, we get:

→ CSA of frustum = 22/7 × 45(7 + 28)

→ CSA of frustum = 22/7 × 45 × 35

→ CSA of frustum = 22 × 45 × 5

→ CSA of frustum = 990 × 5

→ CSA of frustum = 4950.

Hence, the frustum of bucket is 4950cm².

Answer 2

✪ Correct Question :

• ➪ The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is ?

✪ Required Solution :

✯ Values given to us :

• ➪ radius of top bucket (r1) = 45 cm

• ➪ radius of bottom (r2) = 28 cm

• ➪ slant height of bucket (l) = 7 cm

✯ To find :

• ➪vcurved surface area of bucket (csa) ?

✯ Using formula of frustrum of cone :

• ➪ formula = π (r1 + r2) l

✪ Now putting values given :

• ➪ 22/7 × (28 + 7 ) cm × 45

• ➪ 22 × 35 × 45 / 7 cm²

• ➪ 22 × 5 × 45 cm²

• ➪ 110 × 45 cm²

• ➪ 4950 cm² ( Answer)

➲ ✰ CSA of the bucket is 4950 cm²

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