Question

the radii of top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm respectively Find the CSA of bucket

Answer 1

$csa \: of \: frustum = \pi \: (r1 + r2)l \\ = \frac{22}{7} \times (28 + 7) \times 45 \\ = \frac{22 \times 35 \times 45}{7} \\ = 22 \times 5 \times 45 \\ = 110 \times 45 \\ = 4950 {cm}^{2}$

Answer 2

The CSA of the bucket is ‭4947.8625‬ sq. cm.

• The top and bottom radius of the bucket is given as 28 cm and 7 cm.
• Slant height of the bucket is 45 cm.
• CSA (Curved Surface Area) = π(r₁+r₂)l
• Substituting the values and obtaining the CSA of the bucket,

CSA = π(r₁+r₂)l

CSA = π(28+7)×45

CSA = ‭4947.8625‬ sq. cm

The curved surface area of the bucket is ‭4947.8625‬ cm².