the radii of two circle are 19cm and 9cm respectively Find the radius of circle which has circumference equal to the sum of the circumference of the two circle
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radius of 1st circle= 19cm
circumference=2 π radius
circumference= 836/7
radius of 2nd circle= 9cm
circumference=2π radius
circumference= 396/7
the radius of 3rd circle =?
circumference= sum of 1st and 2nd
circumference= 1232/7
circumference= 2π radius
1232/7=. 2* 22/7 radius
1232/7*7= 44radius
1232/44= radius of 3rd circle
radius of third circle is 28 cm
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circumference=2 π radius
circumference= 836/7
radius of 2nd circle= 9cm
circumference=2π radius
circumference= 396/7
the radius of 3rd circle =?
circumference= sum of 1st and 2nd
circumference= 1232/7
circumference= 2π radius
1232/7=. 2* 22/7 radius
1232/7*7= 44radius
1232/44= radius of 3rd circle
radius of third circle is 28 cm
hope it helped
thanks
please mark as brainliest
isha174:
thnks
Answered by
3
Given , Radius of first circle =19cm
Radius of second circle =9cm
Circumference of circle I =2πr=2×22/7×19=119.4
Circumference of circle II=2×22/7×9=56.5
Given that... Circumference of first CIRCLE+ circumference of second CIRCLE=Circumference of Third circle
119.4+56.5=2πr
175.9=2πr
r=175.9×7/22×2
r=1231.3/44
r=28cm (approx.)
Thank You!
{NOTE: the answer is exactly 28..you can get it by not converting circumference into decimals..on keeping it in fraction form and then solving the answer will be 28cm}
Radius of second circle =9cm
Circumference of circle I =2πr=2×22/7×19=119.4
Circumference of circle II=2×22/7×9=56.5
Given that... Circumference of first CIRCLE+ circumference of second CIRCLE=Circumference of Third circle
119.4+56.5=2πr
175.9=2πr
r=175.9×7/22×2
r=1231.3/44
r=28cm (approx.)
Thank You!
{NOTE: the answer is exactly 28..you can get it by not converting circumference into decimals..on keeping it in fraction form and then solving the answer will be 28cm}
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