The radii of two circles are 19 cm and 9 CM respectively find the radius of the circle which has circumference equal to the sum of the circumference of the two circle
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The radius of first circle is 19 cm
So circumference will be =2πr
=2×22÷7×19=396÷7 cm
The radius of second circle is 9 cm
So circumference will be =2πr=2×22÷7×9=836÷7 cm
The sum of the circumference of the two circles will be =(396÷7)+(836÷7)=1232÷7=176 cm
The required circle's circumference =2πr=176 cm
r = (176÷2π)=176÷(2×22÷7)=(176×7)÷(2×22)
=28 cm
Therefore the required circle's radius is 28 cm
Hope it helps you !!!!!
Please mark it as brainliest!!
So circumference will be =2πr
=2×22÷7×19=396÷7 cm
The radius of second circle is 9 cm
So circumference will be =2πr=2×22÷7×9=836÷7 cm
The sum of the circumference of the two circles will be =(396÷7)+(836÷7)=1232÷7=176 cm
The required circle's circumference =2πr=176 cm
r = (176÷2π)=176÷(2×22÷7)=(176×7)÷(2×22)
=28 cm
Therefore the required circle's radius is 28 cm
Hope it helps you !!!!!
Please mark it as brainliest!!
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We've to find out the radius of the circle which has circumference equal to the sum of the circumference of the two circle.
Circumference of Both the circles is 38π & 18π.
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Circumference of third Circle = Circumference of 1st circle + circumference of 2nd circle.
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