the radii of two circles are 19 cm and 9 cm respectively find the radius of the circle which is circumference equal to the sum of the circumference of the two circles
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Radius ( r1 ) of 1st circle = 19 cm
Radius ( r2 ) or 2nd circle = 9 cm
Let the radius of 3rd circle be r .
Circumference of 1st circle = 21tr1 = 21 ( 19 ) = 38π
Circumference of 2nd circle = 2nr2 = 21 ( 9 ) = 18π
Circumference of 3rd circle = 2πr
Given that ,
Circumference of 3rd circle =
Circumference of 1st circle + Circumference of 2nd circle
2πr = 38π + 18π = 56π
r =56π / 2π = 28
Therefore, the radius of the circle which has circumference equal to the sum of the circumference of the given two circles is 28 cm.
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Answer:
Let the radius of 3rd circle be r. Therefore, the radius of the circle which has circumference equal to the sum of the circumference of the given two circles is 28 cm.
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