The radii of two circles are 19 cm and 9 cm respectively. Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles.
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r=28cm this is the radius of the required circle
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☜☆☞hey friend ☜☆☞
here is your answer ☞
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Radius (r1) of 1st circle = 19 cm
Radius (r2) or 2nd circle = 9 cm
Let the radius of 3rd circle be r.
Circumference of 1st circle = 2πr1 = 2π (19) = 38π
Circumference of 2nd circle = 2πr2 = 2π (9) = 18π
Circumference of 3rd circle = 2πr
Given that,
Circumference of 3rd circle = Circumference of 1st circle + Circumference of 2nd circle
2πr = 38π + 18π = 56π
→ r = 28 CM ________answer
Therefore, the radius of the circle which has circumference equal to the sum of the circumference of the given two circles is 28 cm.
hope it will help you
Devil_king ▄︻̷̿┻̿═━一
here is your answer ☞
→_→→_→→_→→_→→_→
Radius (r1) of 1st circle = 19 cm
Radius (r2) or 2nd circle = 9 cm
Let the radius of 3rd circle be r.
Circumference of 1st circle = 2πr1 = 2π (19) = 38π
Circumference of 2nd circle = 2πr2 = 2π (9) = 18π
Circumference of 3rd circle = 2πr
Given that,
Circumference of 3rd circle = Circumference of 1st circle + Circumference of 2nd circle
2πr = 38π + 18π = 56π
→ r = 28 CM ________answer
Therefore, the radius of the circle which has circumference equal to the sum of the circumference of the given two circles is 28 cm.
hope it will help you
Devil_king ▄︻̷̿┻̿═━一
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