the radii of two circles are 19 cm and 9 cm respectively . find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles
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CASE 1
R=19C.M
P=2PI×R
=(2×22×19)/7
= 44×19/7
CASE 2
R=9C.M
P=2PI×R
=(2×22×9)/7
=44×9/7
CASE 3
TOTAL P= (44×19+44×9)/7
=44×28/7
44×4
176C.M
176=2×PI×R
=2×22×R/7
44×R/7
R=176×7÷44
=28C.M
R=19C.M
P=2PI×R
=(2×22×19)/7
= 44×19/7
CASE 2
R=9C.M
P=2PI×R
=(2×22×9)/7
=44×9/7
CASE 3
TOTAL P= (44×19+44×9)/7
=44×28/7
44×4
176C.M
176=2×PI×R
=2×22×R/7
44×R/7
R=176×7÷44
=28C.M
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