the radii of two circles are 25cm and 18cm find the radius of the circle which has circumference equal to the sum of circumference of these two circles
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Answered by
18
hello frnd!!
here's ur answer...
circumference of circle(radius=25cm)=2πr
=2×22/7×25
=44/7×25
=1100/7cm
circumference of circle(radius=18cm)=2πr
=2×22/7×18
=44/7×18
=792/7cm
sum of their circumference=1100+792/7
=1892/7cm
circumference of the circle=1892/7
2πr=1892/7
2×22/7×r=1892/7
44/7×r=1892/7
r=1892/7×7/44
r=43cm
therefore radius of the circle whose circumference is the sum of circumference of the two circle is 43cm.
hope this helps...
here's ur answer...
circumference of circle(radius=25cm)=2πr
=2×22/7×25
=44/7×25
=1100/7cm
circumference of circle(radius=18cm)=2πr
=2×22/7×18
=44/7×18
=792/7cm
sum of their circumference=1100+792/7
=1892/7cm
circumference of the circle=1892/7
2πr=1892/7
2×22/7×r=1892/7
44/7×r=1892/7
r=1892/7×7/44
r=43cm
therefore radius of the circle whose circumference is the sum of circumference of the two circle is 43cm.
hope this helps...
circleii:
43 is the answer in our text
Answered by
8
r1=25 cm
r2=18 cm
C1=2πr1 and C2=2πr2 , where c is circumference.
Let, the radius of required circle be r and its circumference be 2πr
According to the question, we get
2πr=2πr1+2πr2
2πr=2π(r1+r2)
r=r1+r2
Since r1=25 and r2=18
So, we get the radius of the required circle is
r=(25+18) cm =43 cm ans
r2=18 cm
C1=2πr1 and C2=2πr2 , where c is circumference.
Let, the radius of required circle be r and its circumference be 2πr
According to the question, we get
2πr=2πr1+2πr2
2πr=2π(r1+r2)
r=r1+r2
Since r1=25 and r2=18
So, we get the radius of the required circle is
r=(25+18) cm =43 cm ans
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