the radii of two circles are 48 cm and 13 cm.Find the area of the circle which has its circumference equal to the difference of the circumferences of the given two circles.
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radius of 2 circles = 48 cm and 13 cm
let one circle be A having radius 48 cm and the other circle be B having radius 13 cm
circumference of circle A = (2 * 22/7*48) cm
=301.71 cm
circumference of circle B =(2*22/7*13)cm
=81.71cm
difference between the circumferences =(301.71-81.71)cm
=220 cm
so now lets consider a third circle C which has circumference equal to 220 cm
therefore , A.T.P
2*22/7*r=220
or,r=35
therefore, area of circle C = (22/7*35*35)cm
=3850 sq.cm
let one circle be A having radius 48 cm and the other circle be B having radius 13 cm
circumference of circle A = (2 * 22/7*48) cm
=301.71 cm
circumference of circle B =(2*22/7*13)cm
=81.71cm
difference between the circumferences =(301.71-81.71)cm
=220 cm
so now lets consider a third circle C which has circumference equal to 220 cm
therefore , A.T.P
2*22/7*r=220
or,r=35
therefore, area of circle C = (22/7*35*35)cm
=3850 sq.cm
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