the radii of two circles are 4cm and 3cm .find the diameter of tge circle having area equal to the sum of the area of two circles
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Let R=4cm & r=3cm Let the required radius be R'
Area of the circle with radius R = piR2
=pi[4]2
=16pi cm2
Area of the circle with radius r = pir2
=pi[3]2
=9pi cm2
Therefore the area of the circlr with radius R' = area of circles with radius r + area of circle with radius R
piR' 2 =16pi + 9pi
pi R' 2= pi [16+9]
{ pi gets cancelled }
R'2 =25
R' = 5cm
Therefore the new radius is 5cm
Circumference=2piR'
=2 x 22/7 x 5
=31.42 cm [aprox]
Aditya Sarwate answered this
its very easy
let the radii of first circle be r1=4cm
and radii of another circle be r2=3cm.
Area of first circle=2πr1
=2*π*4
=8πcm.
Area of second circle=2πr2
=2*π*3
=6πcm.
ATQ [According to given condition]
Area of first circle+Area of second circle=Area of bigger circle
=8π+6π=2πR
=14π=2πR
R=7cm.
Radius of bigger circle=7cm
Its circumfrence=2πR
=2*22/7*7
=44cm.
Answer.
Area of the circle with radius R = piR2
=pi[4]2
=16pi cm2
Area of the circle with radius r = pir2
=pi[3]2
=9pi cm2
Therefore the area of the circlr with radius R' = area of circles with radius r + area of circle with radius R
piR' 2 =16pi + 9pi
pi R' 2= pi [16+9]
{ pi gets cancelled }
R'2 =25
R' = 5cm
Therefore the new radius is 5cm
Circumference=2piR'
=2 x 22/7 x 5
=31.42 cm [aprox]
Aditya Sarwate answered this
its very easy
let the radii of first circle be r1=4cm
and radii of another circle be r2=3cm.
Area of first circle=2πr1
=2*π*4
=8πcm.
Area of second circle=2πr2
=2*π*3
=6πcm.
ATQ [According to given condition]
Area of first circle+Area of second circle=Area of bigger circle
=8π+6π=2πR
=14π=2πR
R=7cm.
Radius of bigger circle=7cm
Its circumfrence=2πR
=2*22/7*7
=44cm.
Answer.
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3
hope it helps.......
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