Math, asked by jassie80, 1 year ago

the radii of two circles are 8cm and 6cm respectively. find the radius of the circle having area equal to the sum of the areas of the two circles​

Answers

Answered by Nereida
37

\huge\star{\red{\underline{\mathfrak{Answer :-}}}}

10 cm

\huge\star{\red{\underline{\mathfrak{Explanation :-}}}}

Given :-

The radius of first circle = 8 cm

The radius of second circle = 6 cm

The sum of the areas of circle 1 and 2 who is equal to the area of third circle.

To find :-

The radius of third circle.

Solution :-

Area of first circle = \pi \times  {8}^{2}

Area of second circle = \pi \times  {6}^{2}

Area of third circle = \pi \times  {r}^{2}

So, because this sum of the areas of first to circles is equal to the area of third circle.

\implies(\pi \times  {8}^{2} ) + (\pi \times  {6}^{2} ) = (\pi \times  {r}^{2} )

\implies \cancel {\pi }\: ( {8}^{2}  +  {6}^{2} ) = \cancel {\pi }\times  {r}^{2}

\implies {8}^{2}  +  {6}^{2}  =  {r}^{2}

\implies r \:  =  \sqrt{ {8}^{2}  +  {6}^{2} }

\implies r \:  =  \sqrt{64 + 36}

\implies r = \sqrt{100}

\implies r \:  = 10 \: cm

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Formula used :-

Area of a circle = \pi \times  {r}^{2}

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Answered by Anonymous
15

Given ,

 \starRadius of first circle (r1) = 8 cm

 \starRadius of second circle (r2) = 6 cm

 \pink{ \sf \fbox{ \fbox{The \:  sum \:  of  \:   area \:  of \:  first \:  and  \: second  \: circle = area \:  of \:  third \:  circle  }}}

Let , the radius of third circle be r3

According to the question ,

 \sf \hookrightarrow \pi (r_{1} ) (r_{1} ) + \pi (r_{2}) (r_{2}) = \pi (r_{3})(r_{3}) \\  \\  \sf \hookrightarrow \frac{22}{7}  \times 64 +  \frac{22}{7}  \times 36 =  \frac{22}{7}  \times (r_{3})(r_{3}) \\  \\ \sf \hookrightarrow  \frac{1408}{7}  +  \frac{792}{7}  =  \frac{22}{7}  \times  (r_{3})(r_{3}) \\  \\  \sf \hookrightarrow \frac{2200}{7}  =  \frac{22}{7}  \times (r_{3})(r_{3}) \\  \\ \sf \hookrightarrow (r_{3})(r_{3}) =   \frac{ \cancel7 \times 2200}{\cancel 7 \times 22}  \\  \\ \sf \hookrightarrow (r_{3})(r_{3}) =  100 \\  \\ \sf \hookrightarrow r_{3} = 10 \:  \: cm

Hence , the radius of the third circle is 10 cm respectively

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