Question

The radii of two circles are 8cm and 6cm respectively. find the radius of the circle having area equal to the some of the ares of the to circles.​

Answer 1

Answer:

R = 10 cm

Step-by-step explanation:

Let the radius of the required circle be R and radii of two given circles be r1 and r2, then according to question. ⇒ R = 10 cm.

Answer 2

let the radius of the 1st and 2nd circle be r1 and r2

AND....

let the radius of the third circle be r3

NOW THE AREA OF THE 3rd CIRCLE IS SAME AS THE SUM OF AREAS OF 1st and 2nd..

i.e

$\pi {r1}^{2} + \pi {r2}^{2} \: \:$

22/7 × 8×8 + 22/7 ×6×6 = area of the third circle....

201.14 + 113.14= 314.28

the area of the third circle

= 314.28 = pi × r3²

= pi × r3²314.28

= 22/7 × r3²

= pi × r3²314.28 = 22/7 × r3² 99.99 = r3²round off 99.99 to 100...

• then take root on both sides....
• 10 = r3
• therefore the radius of the 3rd circle is 10