the radii of two circles are the 8 cm and 6 CM respectively find the radius of circle having area equal to the sum of the area of two circle
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Answered by
0
πr1^2+πr2^2=πR^2
π{r1^2+r2^2}=πR^2
r1^2+r2^2=R^2
8^2+6^2=R^2
64+36=R^2
√100=R
R=10cm
π{r1^2+r2^2}=πR^2
r1^2+r2^2=R^2
8^2+6^2=R^2
64+36=R^2
√100=R
R=10cm
Answered by
1
R1=8cm R2=6cm
Now according que
2pieR=2pie (r1+r2)
R=r1+r2
R=8+6
R=14cm
Now according que
2pieR=2pie (r1+r2)
R=r1+r2
R=8+6
R=14cm
Omn:
Sry this is wrong
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