Question

The radii of two circular ends of a frustum of a cone shaped dustbin are 15cm and 8cm. If it's depth us 63cm , find the volume of the dustbin

Answer 1

Answer:

Step-by-step explanation:

Volume of frustum=1/3π(r1^2+r2^2+r1*r2)h

r1=15

r2=8

h=63

So,

1/3*22/7(225+64+120)*63

1/3*22/7*409*63

66*409

26994 cm^3

Answer 2

Answer:

Step-by-step explanation:

Given the height or depth of the container $(h)= 63\text{ cm}$

Radius of the upper end $R_{1}=15\text{ cm}$

Radius of the lower end $R_{2}=8\text{ cm}$

The shape of the bucket is frustum.

Volume of the container

$V=\frac{1}{3}\times\pi\timesh\times(R_{1}^{2}+R_{1}R_{2}+R_{2}^{2})\times{h}\\\\\Rightarrow{V}=\frac{1}{3}\times\frac{22}{7}\times(15^{2}+15\times8+8^{2})\times{63}\\\\\Rightarrow{V}=\frac{1}{3}\times\frac{22}{7}\times(225+120+64)\times{63}\\\\\Rightarrow{V}=\frac{1}{3}\times\frac{22}{7}\times409\times{63}\\\\\Rightarrow{V}=26994\text{ cm}^{3}$