Question

the radii of two circular ends of items shaped bucket are 14 cm and 7 cm height of the bucket is 30 cm how many litres of water it can hold​

Answer 1

Explanation:

Let the radii be r1 and r2 and height be h

Then volume is given by

\begin{lgathered}\frac{\pi \times h}{3} \times ( {(r1)}^{2} + r1r2 + {(r2)}^{2} ) \\ = \frac{\pi \times 30}{3} \times ( {14}^{2} + 14 \times 7 + {7}^{2} ) \\ 10\pi \times 343 = 10780 \: {cm}^{3} \\ = 10.78 \: litres\end{lgathered}

3

π×h

×((r1)

2

+r1r2+(r2)

2

)

=

3

π×30

×(14

2

+14×7+7

2

)

10π×343=10780cm

3

=10.78litres

Answer 2

Given:

• $\sf{r_1 = 14cm.}$

• $\sf{r_2 = 7cm.}$

• $\sf{h = 30cm.}$

To Find:

• Volume of bucket = ?

Formula Used:

$\star \: \boxed{\bf\red{Volume \: of \: bucket = \frac{1}{3} \pi ( {r_1}^{2} + \: {r_2}^{2} + r_1 \times r_2)}}$

Solution:

Substituting Values,

$:\implies\mathtt{\frac{1}{3} \times \frac{22}{7} \times ( {14}^{2} + {7}^{2} + 14 \times 7) \times 30}$

$:\implies\mathtt{1 \times \frac{22}{7} \times (196 + 49 + 98) \times 10}$

$:\implies\mathtt{ \frac{22}{7} \times 343 \times 10}$

$:\implies\mathtt{10780 {cm}^{3} }$

$:\implies\mathtt{ \frac{10780}{1000} .... \: (1 \: litre \: = 1000 {cm}^{3)} }$

$:\implies\mathtt{\dfrac{\cancel{10780}}{\cancel{1000}}}$

$\sf\star \: \underbrace\blue{Volume \: of \: bucket = 10.78 \: Litres} \: \star$

Hence,

• Bucket can hold 10.78 litres of water.