The radii of two concentric circles are 13 cm and 8 cm. AB is the diameter of the bigger circle touching it at D. Find find length of AD.
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join AD and AE
proof - in triangle ODE
(by pyathgoras therom)
OD²=OB²-OD²
DB²=(13)²-(8)10
DB=/105
ED=/105 (as perpendicular OD from the centre of the circle O ,to a chord ED bisect the chord )
in triangle AEB
LAEB =90° ( as angle one semi circle is a right angle )
OD//AE
OD=1/2 AE ( segment joining the mid point of any 2 sides of a traingle is // to the third side also half of it )
AE= 16
in triangle AED
AD²= 16²+(105root)²
AD²= 256+105
AD²=361root
AD=19 ✓
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