Question

the radii of two cylinder es are in the ratio 3:2 and their hight are the ratio 4:5calculate the ratio of their curved surfes area

Answer 1

$let \: radii \: of \: two \: cylinder \: be \: r1 \: and \: r2 \\ \frac{r1}{r2} = \frac{3}{2} \\ = > r1 = 3k \\ = > r2 = 2k \\ and \: let \: height \: be \: h1 \: nd \: h2 \\ \frac{h1}{h2} = \frac{4}{5} \\ = > h1 = 4h \\ = > h2 = 5h \\ accorcding \: to \: ques \\ \frac{curved \: surface \: area \: of \: first \: cylinder}{curved \: surface \: area \: of \: second \:cylinder} = \frac{2\pi \: r1h1}{2pi r2h2 } \\ = \frac{2 \times 3k \times 4h}{2 \times 2k \times 5h} \\ = \frac{6}{5} =6:5\\ \bold{hope \: its \: helpful \: to \: you}$