the radii of two of first four bohr orbits of hydrogen atom are in ratio of 1 is to 4.the energy difference between them may be
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Answer:
As we know,
r
n
∝n
2
r
n
1
r
n
2
=
1
4
=2
2
/1
1
=4
2
/2
2
so
The two orbits are either I and II or II and IV
Also, we know that,
E
n
∝−Z
2
/n
2
and E
n
=−13.6×Z
2
/n
2
Thus, E
2
−E
1
=
4
−13.6
+13.6=10.2eV
and E
4
−E
2
=
16
−13.6
+
4
13.6
=2.55eV
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