The radii of two planets are r and 2r respectively and there density p or p/2, what is the radio acceleration due to gravity at their surface ,at what height the acceleration due to become g/9.
Answers
Answered by
0
Acc due to gravity at the surface of planet = g = (4/3) GRλp
Planet 1; R = R
p = P
so,
g1 = (4/3) GRλP
planet 2 ; R = 2R
p = P/2
so,
g2 = (4/3) G2RλP/2
or
g2 = (4/3) GRλP
thus g1 = g2
ratio will be 1:1
Planet 1; R = R
p = P
so,
g1 = (4/3) GRλP
planet 2 ; R = 2R
p = P/2
so,
g2 = (4/3) G2RλP/2
or
g2 = (4/3) GRλP
thus g1 = g2
ratio will be 1:1
Similar questions