the radii of two right circular cylinders are in the ratio 2:3 and ther heights are in the ratio 5:4. Calculate the ratio of their curved surface areas
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6
so given ![\frac{r_1}{r_2}=\frac{2}{3} \frac{r_1}{r_2}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Br_1%7D%7Br_2%7D%3D%5Cfrac%7B2%7D%7B3%7D)
and
![\frac{h_1}{h_2}=\frac{5}{4} \frac{h_1}{h_2}=\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bh_1%7D%7Bh_2%7D%3D%5Cfrac%7B5%7D%7B4%7D)
so curved surface are = 2πrh
So we have to find the ratio of 2πr₁h₁/2πr₂h₂ = r₁h₁/r₂h₂ =
![\frac{h_1}{h_2}*\frac{r_1}{r_2} \frac{h_1}{h_2}*\frac{r_1}{r_2}](https://tex.z-dn.net/?f=%5Cfrac%7Bh_1%7D%7Bh_2%7D%2A%5Cfrac%7Br_1%7D%7Br_2%7D)
= 5/6
so the ratio is 5 : 6 ANSWER
and
so curved surface are = 2πrh
So we have to find the ratio of 2πr₁h₁/2πr₂h₂ = r₁h₁/r₂h₂ =
= 5/6
so the ratio is 5 : 6 ANSWER
Anonymous:
hope it helps
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