Question

The radio of the ends of a frustum of a cone 40cm high are 38cm and 8cm. Its slant height is​

Answer 1

Answer:

answer is 54

I hope this will help you

Answer 2

Answer:

The answer is 50cm.

Step-by-step explanation:

R1 = 38cm

R2 = 8cm

h = 40cm

Slant height =

$= > \: \sqrt{ {h}^{2} + {(r1 - r2)}^{2} }$

$= > \: \sqrt{ {40}^{2} + {(38 - 8)}^{2} }$

$= > \: \sqrt{1400 + 900}$

$= > \: \sqrt{2500}$

$= > \: 50$

So, the slant height of frustum is 50cm.