Physics, asked by Mousaeed280, 11 months ago

The radionuclide 11C decays according to 116c → 115B + e+ + v : T1/2 = 20.3 min The maximum energy of the emitted positron is 0.960 MeV. Given the mass values: m(116C) = 11.011434 u and m(116B) = 11.009305, calculate Q and compare it with the maximum energy of the positron emitted

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Answered by arpandas2341

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