The radious of the first Bohr orbit of H-atom is 0.529×10^-10m.then what will be the radious of the second orbit of He+ ion?
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since radius formula is 0.529n^2/z
0.529×10^-10=0.529×n^2/1
therefore n^2=10^-10
for helium radius is 0.529×10^-10/2
therefore r=0.2645×10^-10
0.529×10^-10=0.529×n^2/1
therefore n^2=10^-10
for helium radius is 0.529×10^-10/2
therefore r=0.2645×10^-10
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