The radius and height of a cone are each increased by 20% then the volume of the cone is increased by what percentage?
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Volume of a cone = πr²h/3
New radius = 6r/5
New height = 6h/5
New volume = 1/3 π (6r/5)^2(6h/5)
= πr^2h 72/125
Volume % increase = (New volume/Old volume×100) -100
= (πr^2h 72×3 / πr^2h 125 × 100) -100
= (1.728×100) -100
= 172.8 - 100
= 72.8%
New radius = 6r/5
New height = 6h/5
New volume = 1/3 π (6r/5)^2(6h/5)
= πr^2h 72/125
Volume % increase = (New volume/Old volume×100) -100
= (πr^2h 72×3 / πr^2h 125 × 100) -100
= (1.728×100) -100
= 172.8 - 100
= 72.8%
Lipimishra2:
If you have a doubt, feel free to ask.
Thnx a lot.....
You're welcome!
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