the radius and height of a cone is changing such that height is always 1/3 of the radius .if radius is changing at the rate of 4 cm/s . find the rate change of volume when radius 10cm.
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Answer:
it is related answer fill your value and solve
Explanation:
Let hand r be the height and radius of cylinder
Given that,
dt
dr
=3m/s,
dt
dh
=−4m/s
Also, V=πr
2
h
On differentiating with respect to t, we get
dt
dv
=πr
2
dt
dh
+h.2r
dt
dr
At r=4m and h=6 m
∴
dt
DV
=π−64+144=80πm
3
/s
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