Question

The radius and height of a right circular cylinder is 3y cm and 2x CM respectively, find its curved surface area

Answer 1

Answer:

$\bigstar{\bold{CSA\:=\:37.68xy\:cm^{2} }}$

Step-by-step explanation:

$\Large{\underline{\underline{\it{Given:}}}}$

• Radius (r) = 3y cm
• Height (h) = 2x cm

$\Large{\underline{\underline{\it{To\:Find:}}}}$

• Curved surface area (CSA)

$\Large{\underline{\underline{\it{Solution:}}}}$

→ The CSA of a cylinder is given by the formula

   CSA = 2πrh

→ Substituting the given datas, we get

  CSA = 2 × 3.14 × 3y × 2x

$\boxed{\bold{CSA\:=\:37.68xy\:cm^{2} }}$

$\Large{\underline{\underline{\it{Notes:}}}}$

→ The CSA of a cylinder is given by the formula

   CSA = 2πrh

→ The TSA of a cylinder is given by the formula

   TSA = 2πr (r + h)

Answer 2

Given ,

The radius and height of a right circular cylinder are 3y cm and 2x cm

We know that , the curved surface area of cylinder is given by

$\boxed{ \sf{CSA = 2\pi rh}}$

Thus ,

CSA = 2 × 22/7 × 3y × 2x

CSA = (44 × 6yx)/7

CSA = 264yx/7

CSA = 37.6 cm²

Therefore ,

The CSA of cylinder is 37.6 cm²