The radius and height of a solid right circular cone are in the ratio of 5:12. If its volume is 314 cm2
,find its total surface area.( = 3.14)
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Answer:
Ratio of radius and height of a right circular cone is 5:12
let the radius and height be 5x and 12x respectively
The slant height of cone by Pythagoras theorem will be 13x (5x^2+12x^2= slant height ^2 means l^2)
volume of cone is 314 cm cube
hence 1/3πR^2H=314 (π=3.14 -given)
1/3×3.14×5x^2×12x=314
1/3×25x^2×12x=314÷3.14
25x^2×4x=100
100x^3=100
x^3=1
x=1
so Radius of cone=5x=5cm
Height of cone=12x=12cm
and slant height of cone (l)=13x=13cm
Now, TSA of cone= πRl+πR^2
=πR(l+R)
=3.14×5(13+5)
=15.7×18
=282.6cm square
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