The radius and height of a solid right-circular cone are in the ratio of 5:12.if its volume is 314 cm^3 ,find its tsa.
Answers
Answer:
TSA = 282.6 cm²
Step-by-step explanation:
Given that radius and height are in the ratio of 5:12.
Let the radius and height be 5x, 12x respectively.
It is given that Volume of cone = 314 cm³.
⇒ (1/3) * πr²h = 314
⇒ (1/3) * π * (5x)² * (12x) = 314
⇒ (1/3) * 3.14 * 25x² * 12x = 314
⇒ 300x³ = 300
⇒ x³ = 1
⇒ x = 1.
Hence:
⇒ Radius = 5 cm.
⇒ Height = 7 cm.
We know that slant height(l) = √h² + r²
⇒ √12² + 5²
⇒ √144 + 25
⇒ √169
⇒ 13 cm.
Now,
We know that Total surface area = πr(l + r)
= 3.14 * 5 * (13 + 5)
= 3.14 * 5 * (18)
= 282. 6 cm².
Therefore, Total surface area = 282. 6 cm².
Hope it helps!
Step-by-step explanation:
Given r:h = 5:12
Let r = 5x and h = 12x
Volume of cone = 314 cm3
That is (1/3)πr2h = 314
(1/3) × (3.14) × (5x)2 × 12x = 314
25x2 × 12x = 100 × 3
x3 = 1
Hence x = 1
Therefore, r = 5 cm and h = 12 cm
Slant height, l = √[r2 + h2]
= √[52 + 122] = √169
Therefore, slant height = 13 cm