The radius and slant height of cone are in the ratio 3:5 if its csa is 2310 find its radius height and slant height
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Answered by
12
let radius = 3x and slant height = 5x
csa of cone = π*r*l
2310= 22/7 * 3x * 5x
2310= 330x² / 7
2310*7/330 = x²
49 = x²
x = 7
radius = 3x = 3*7 = 21
slant height = 5x = 5*7 = 35
csa of cone = π*r*l
2310= 22/7 * 3x * 5x
2310= 330x² / 7
2310*7/330 = x²
49 = x²
x = 7
radius = 3x = 3*7 = 21
slant height = 5x = 5*7 = 35
Answered by
4
Radius and slant height of cone are in ratio-3:5
And,CSA=2310
let,the radius and slant height of cone = r and l,r\l=3\5
Then, r=3\5×l...(1)
Now,we know that:-
CSA of cone=(πrl).
2310=(22\7×3\5×l×l)
2310=(22\7×3\5×l²)
l²=2310×7×5\22×3
l²=35×35
l=35
Now,put the value of l in eq...(1)
r=3\5×l
r=3\5×35
r=21
So,r=21,l=35
And,CSA=2310
let,the radius and slant height of cone = r and l,r\l=3\5
Then, r=3\5×l...(1)
Now,we know that:-
CSA of cone=(πrl).
2310=(22\7×3\5×l×l)
2310=(22\7×3\5×l²)
l²=2310×7×5\22×3
l²=35×35
l=35
Now,put the value of l in eq...(1)
r=3\5×l
r=3\5×35
r=21
So,r=21,l=35
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