the radius and the height of a cylinder are in ratio 7:3 ,if the volume of the cylinder is12474cm cube find the curved surface Area and the total surface area of cylinder
Answers
the height = h cm
rato of r and h = 7:3
r / h = 7 /3 => r = 7h/ 3
volume = 12474
πr^2h = 12474
(22/ 7) × ( 7h/ 3)^2 × h = 12474
154 h^3 / 9 = 12474
h^3 =( 12474 × 9)/ 154
h^3 = 81 × 9 = 729
h = 9 cm , r = 7h/ 3 = (7 × 9)/ 3 = 21 cm
c.s.a of cylinder = 2πrh
= (2 × 22 × 21 × 9 ) ÷ 7 = 1188 cm^2
total surface area of cylinder
= 2πr ( r + h ) = 2 × (22/ 7) × 21 ( 21 + 9)
= 44 × 3 × 30 = 3960 cm^2
Answer:
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c.s.a = 1188cm^2, t.s.a = 3960 cm^2
Step- by-Step Solution
Volume of cylinder =12474 cm³
Let the no. be =7x,3x
So,
Step
Volume=πr²h
12474=22/7*7x*7x*3x
12474=22*x*7x*3x
12474=22*21x³
21x³=12474/22
21x³=567
x³=567/21
x³=27
x=√27
x=3 cm
Therefore,
r=7x
r=7*3
r=21 cm
h=3x
h=3*3
h=9 cm
So,
Curved S.A=2πrh
=2*22/7*21*9
=44*27
=1188 cm²
T.S.A=2πrh+2πr²
=1188 cm²+2*22/7*21*21
=1188 cm²+44*63
=1188 cm²+2772 cm²
=3960 cm²
Answer-
r=21 cm h=9 cm
Curved S.A=1188 cm²
T.S.A=3960 cm²