Question

The radius if a sphere is 5.3±0.1cm. Calculate the percentage error in its volume. Spams will be reported. I want full description.​

Answer 1

Answer :

Radius of the sphere = 5.3±0.1 cm

Volume of the sphere = (4/3)πr³

⇒ (4/3)×3.14×(5.3)³

⇒ (4/3)×3.14×148.877

⇒ (4/3)×467.47

⇒ 623.30 cm³

Now, ∆V/V = 3(∆r/r)

We need to find ∆V.

So, ∆V = 3(∆r/r)×V

➸ ∆V = 3(0.1/5.3)×623.30

➸ ∆V = 3×0.0188×623.30

➸ ∆V = 0.0564×623.30

➸ ∆V = 35.15 cm³

So, Percentage error of he volume :

➜ (∆V/V)×100

➜ (35.15/623.30)×100

➜ (0.056)×100

➜ 5.6 %

Hence, The Answer : 5.6 %

Answer 2

Answer:

See The Attachment Your Answer.