the radius,in centimetres , of the greatest sphere that can be craved out of a solid cone of radius 9 cm and height 40 cm , is
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Step-by-step explanation:
The greatest sphere that can be carved out of a solid cone of radius 9 cm and height 40 cm is :
Slant height of sphere = l²= h²+ r²
l² = 40² +9²
l² = 1681
l = 41 meter
Let the greatest sphere has radius R.
As sphere will touch the base as well as other two sides of the cone.
Line segment PS will be tangent to the sphere at point M.
So, ∠PMO= 90°
As, PR ⊥ QS, ∠PRS = 90°
In Δ PRS, and Δ PMO
m∠PRS = m∠PMO = 90°
∠MPR = ∠SPR [Common Angles]
By AA postulate of Similarity of triangles. We get, ΔPRS ~ ΔPMO
As triangles are similar their sides will be proportional :
PM/PR = MO/RS =PO/PS
R/9= 40-R/41
9(40-R)=41R
360-9R=41R
360=50R
R=360/50=7.2
MARK BRAINLIEST
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