Question

the radius is a conical tant is 7meter and its height is 10meter. calculate the length of canvas used in making the tent if width of canvas is 2m.( use π =22/7)?​

Answer 1

the length of canvas used to make the tent can be found through the CSA of cone

csa of cone = πrl

here r=7m

l= √h^2+r^2

l= .√10^2+7^2

l= √100+49

l=√149

substitute it in the formula

=22/7(7)(√149)

=22(√149)

=22(12.2)

=268.4m^2

here 268.5m^2 of cloth is used

length of cloth if breadth is 2m =

area=length(breadth)

268.4=length(2)

268.4/2=length

length=134.2m

so 134.5m of cloth is required to make the tent

Answer 2

Given,

The radius is a conical tent is 7meter and its height is 10meter.

The width of the canvas is 2m.

To find out,

The length of canvas used in making the tent.

Solution:

The radius of a conical tent (r) = 7 metres and height (h) = 10 meters.

$slant \: height \: of \: the \: cone \\ \: {l}^{2} = {r}^{2} + {h}^{2} \\l \: = \sqrt{ {r}^{2} + {h}^{2} } \\l = \sqrt{49 + 100 } \\ l = \sqrt{149} \\ l = 12.2 \: meters$

Now, surface area of the tent = πrl

$surface \: area \: of \: the \: tent = \frac{22}{7} \times 7 \times 12.2</strong></p><p><strong>[tex]surface \: area \: of \: the \: tent = \frac{22}{7} \times 7 \times 12.2$

$surface \: area \: of \: the \: tent = 268.4 {m}^{2} </strong></p><p><strong>[tex]surface \: area \: of \: the \: tent = 268.4 {m}^{2}$

$The \: area \: of \: canvas \: used \: = 268.4 {m}^{2}$

It is given that the width of the canvas = 2m

$length \: of \: canvas \: used \: = \frac{area}{width} = \frac{268.4}{2} = 134.2 \: meters$

Therefore the width of the canvas used is 134.2 meters.