Question

The radius of 10th orbit of hydrogen atom

Answer 1

Answer:

Answer:The Bohr radius (a0 or rBohr) is a physical constant, approximately equal to the most probable distance between the nucleus and the electron in a hydrogen atom in its ground state. It is named after Niels Bohr, due to its role in the Bohr model of an atom. Its value is 5.29177210903(80)×10−11 m.

Answer:The Bohr radius (a0 or rBohr) is a physical constant, approximately equal to the most probable distance between the nucleus and the electron in a hydrogen atom in its ground state. It is named after Niels Bohr, due to its role in the Bohr model of an atom. Its value is 5.29177210903(80)×10−11 m.Named after: Niels Bohr

Answer:The Bohr radius (a0 or rBohr) is a physical constant, approximately equal to the most probable distance between the nucleus and the electron in a hydrogen atom in its ground state. It is named after Niels Bohr, due to its role in the Bohr model of an atom. Its value is 5.29177210903(80)×10−11 m.Named after: Niels BohrSymbol: a0 or rBohr

Answer:The Bohr radius (a0 or rBohr) is a physical constant, approximately equal to the most probable distance between the nucleus and the electron in a hydrogen atom in its ground state. It is named after Niels Bohr, due to its role in the Bohr model of an atom. Its value is 5.29177210903(80)×10−11 m.Named after: Niels BohrSymbol: a0 or rBohrNatural units: 2.68×10−4/eV; 3.27×1024 ℓP

Answer:The Bohr radius (a0 or rBohr) is a physical constant, approximately equal to the most probable distance between the nucleus and the electron in a hydrogen atom in its ground state. It is named after Niels Bohr, due to its role in the Bohr model of an atom. Its value is 5.29177210903(80)×10−11 m.Named after: Niels BohrSymbol: a0 or rBohrNatural units: 2.68×10−4/eV; 3.27×1024 ℓPSI units: 5.29×10−11 m

Answer 2

The radius of 10th orbit of hydrogen atom is

Explanation:

Radius of an atom is given by the Bohrs equation:

$r=\frac{0.529\times n^2}{Z}A^0$

where,

r = radius of atom

n = number of orbit, for first n = 1, for second n = 2 and so on.

Z = Atomic number = 1 (for hydrogen)

$r=\frac{0.529\times 10^2}{1}A^0$

$r=52.9A^0$    

Thus radius of 10th orbit of hydrogen atom is $5.29A^0$

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