Question

the radius of 3rd orbit of li2+ is

Answer 1

✌✌✌✌✌✌✌✌✌✌✌✌
●•••••••••Hello User••••••••••••●
《《Here is your answer》》
_______________________
Follow the attachment :)
_______________________

●••••••☆Brainly Star☆••••••••●
✌✌✌✌✌✌✌✌✌✌✌✌

Answer 2

Given:

The ion li2+.

To Find:

The radius of the 3rd orbit of li2+.

Solution:

To find the radius of the 3rd orbit of li2+ we will follow the following steps:

As we know,

The radius of a hydrogen-like an atom is given by the formula:

radius

$\frac{4п ео n²z }{m { {z}^{2} e}^{2} }$

eo= permittivity of free space

n = energy level

m = electron rest mass

e = elementary charge

The value of $\frac{4п ео}{ {e}^{2} }$

is 0.52 A°.

So, the radius is directly proportional to

$0.52 \frac{ {n}^{2} }{ {z}}$

The value of n for the third orbit of lithium-ion is 3 and z = 3 because the atomic number of lithium is 3.

So, by putting values of n and z we get radius =

$0.52 \frac{ {3}^{2} }{ {3}} = 0.52 \times 3 = 1.56$

Henceforth, the radius of the 3rd orbit of li2+ is 1.56 A°.