the radius of a atom is 220 pm. if it crystallizes a face centered cubic lattice. what is the length of the side of the unit cell.
Answers
Answered by
18
Answer:
628.5pm
Explanation:
in fcc,
4r=√2a
4(220)=√2a
a=628.5pm
Answered by
1
Answer:
The edge length of the unit cell crystallized in FCC lattice is equal to 622.35 pm.
Explanation:
We have given, the radius of an atom, r = 220 pm
Give, that the compound is crystallized in face centered cubic lattice (FCC).
The relation between the radius of atom and edge length of the unit cell is:
4r = √2a
where 'a' is the edge length of FCC unit cell.
Substitute the value of 'r' in equation (1), we will get;
4(220) = (1.414)(a)
a = 622.35 pm
Therefore, the length of the side of the unit cell is equal to 622.35 pm.
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