The radius of a ball is (5.0+0.2) cm. The percentage error in the volume of the ball is :
(A). 12%
(B) 4%
(C) 7%
(D) 9%
Answers
Answer ⇒ Option (A). is correct.
Explanation ⇒
Given, Radius of the ball = 5 cm. ± 0.2 cm.
∴ % error = % error in radius/total radius × 100
∴ % error = 0.2/5 × 100 = 4 %
Now, ball is spherical in shape, thus, Volume = 4/3 × πr³
This means, volume is proportional to the third power of radius.
∴ % Error of Volume = 3 × % Error of Radius.
∴ % error of volume = 3 × 4 %
∴ Error in volume = 12 %.
Hence, the %error of volume = 12 %.
Hope it helps.
Answer ⇒ Option (A). is correct.
Explanation ⇒
Given, Radius of the ball = 5 cm. ± 0.2 cm.
∴ % error = % error in radius/total radius × 100
∴ % error = 0.2/5 × 100 = 4 %
Now, ball is spherical in shape, thus, Volume = 4/3 × πr³
This means, volume is proportional to the third power of radius.
∴ % Error of Volume = 3 × % Error of Radius.
∴ % error of volume = 3 × 4 %
∴ Error in volume = 12 %.
Hence, the %error of volume = 12 %.❤️