Question

The Radius of a ball is (5.2±0.2)cm. The %age Error in the Volume of the Ball is(approximately).
Explain briefly each & every step, as answer is known.
[Answer: 11%] ​

Answer 1

Answer:

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Answer 2

volume of a sphere

$v= \frac{4}{3} \pi \: r {}^{3}$

now....

$\frac{dv}{v} = 3 \frac{dr}{r} \\ now \\ = > \frac{dv}{v}\: percent = 3 \times \frac{0.2}{5.2} \times 100 = 11.53 \: percent$