the radius of a ball is (5.2plus minus 0.2)cm the percentage error in the volume of ball
Answers
Answered by
0
Answer:
11.5%
Explanation:
Given:-
Ball(sphere)
Radius=(5.2+_0.2)cm
Volume of sphere =4/3pie radius^3
Percentage error=Error/value×100
=3×(0.2/5.2)×100
=(3/26)×100
=11.5%
Therefore the percentage error in volume of ball is 11.5%
Similar questions