Question

The radius of a circle is 10 cm and a chord of a circle is 12 cm in length. Find the distance of
the chord from the centre of the circle.​

Answer 1

Answer:

Step-by-step explanation:

Correct option is

C

8 cm

Suppose AB is the chord. O is the centre of the circle.  

If OM is the perpendicular drawn from O to AB as its distance, then OAM and OMB are both right angled triangles.

Since, length of the chord is 12cm, both AM and MB =  

2

12

​  

=6 cm

Now, radius of the circle OB=10 cm

Using Pythagoras theorem, we have

⇒OB  

2

=OM  

2

+MB  

2

 

⇒10  

2

=OM  

2

+6  

2

 

⇒OM  

2

=100−36=64

⇒ distance =OM=  

64

​  

=8cm