Question

the radius of a circle is 10 cm and a chord ofa circle is 12 cm in length. Find the distance of

the chord from the centre of the circle.​

Answer 1

Answer:

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Step-by-step explanation:

44 answer

Answer 2

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$∴ \: \: \: AB=10cm$

$\: \: \: \: OC⊥AB \: , OC \: \: bisects \: \: AB \: \:$

$∴ \: \: \: \: \: AC = \frac{AB}{2} = \frac{10}{2} = 5cm \:$

$\: \: \: ∴ \: \: \: In \: ΔAOC \: , ∠C = {90}^{0}$

$∴ \: \: AO² \: = \: AC² \: + \: OC²$

$</p><p> \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [ Pythagorean \: theorem]$

$\: \: \: \: \: {r}^{2} = {5}^{2} + {12}^{2}$

$\: \: \: \: \: {r}^{2} = 25 + 144$

$\: \: \: \: \: {r}^{2} = 165$

$∴ \: \: \: \: r = ± \sqrt{165}$

$\: \: \: \: \: \: \: \: \: \: \: \: r \: = \: \: \: 13cm$