Question

the radius of a circle is 10 cm and the lenth one of its chord is 16 cm find the distance of the chord from the center

Answer 1

Solution:

Given that,

Radius of circle (OA) = 8cm

Chord (AB) = 12cm

Draw OC⊥AB

We know that

The perpendicular from centre to chord bisects the chord

∴AC=BC=122=6cm

Now in ΔOCA, by Pythagoras theorem

AC2 + OC2 = OA2

=>62 + OC2 = 82

=>36 + OC2 = 64

=>OC2 = 64-36

=> OC2 = 28

=>OC = √28

=>OC = 5.291cm

 

Answer 2

Hey,
Draw a perpendicular from point O to the centre of the chord AB which will bisect the chord.
So, Applying Pythagoras theorem,
OA^2=OD^2+AD^2
10^2=OD^2+8^2
OD=6cm.
So, distance of the chord from the centre is 6cm.
Hope this helps you buddy!!
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