The radius of a circle is 10cm and a chord of a circle is 12cm in length. Find
the distance of the chord from the centre of the circle
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At first draw draw a figure of it such that OB=r, AB is chord ,AD be half of the chord, OD be distance of the chord from the centre.
then , we will get a right triangle ODB.
here, OB=10cm
DB=1/2AB=6cm
OD =?
By Pythagoras theorem , we have
OB^2=OD^2+DB^2
so, 10^2=OD^2+6^2
=>OD^2= 100 - 36
=>OD=√64
=>OD=8
Hence, the distance of chord from the centre of the circle is 8cm
ankitgupta82:
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